That question has been asked and answered. In fact, it has a matter of recent discussion. Do you have a need that is beyond what has been already posted?

I don't think the site has a comprehensive list assembled. The search function and exactly what motor you are asking about kind of matters.

 

Any chance you could link?

I searched before and after your post with no specifics to RPM and CI. I found RPM to be approximately 180 RPM, I am guessing at pump turning 3600 rpms.

I am looking at 2xx drive motors. It would be great to know CI also. I am planning for a project, I have a drive motor on the shelf that is good however I would like to compare to commercially available units also.

 

The drive motors are pretty much a constant with the 200/3000 series motors turning at a higher RPM than the 400/4000 series motors with the same pressure/flow rate.
The pumps have been discussed more as there are many available with different RPM, pressure and flow rates.

 

That would cost you way too many cheeseburgers.

I have found gems are found in the dirt by scratching around. The same holds true when searching for specific knowledge.

 

I am assuming you have never asked a question on this site? I could use the help and spent some time looking and reading other threads.

 

So, I think the reason you haven't seen a response on this is because,

Although I've read and searched a lot of the old posts, I've found lots of similar questions but most (if not all) had answer that were more rhetoric in nature then actual answers.

I think, probably the best answer would be, to figure out the formula required to convert into the answer you're looking for. Then, with that formula, input the known data available,
Well, that's a mouth full, without saying a whole lot,

Anyways, finding the answer to that question, alluded me as well when I was looking at possibly having to replace a motor on one of my tillers.

CID= (GPM x 231)/RPM

So, a simple check,, 9 X 231/3600 = .557 which is "somewhat close" to what our pumps are rated for.

Of course, this one is fairly easy because it's a pump,, but with a hydr motor, the input would be gal/min, and figuring the rpm, well, not so easy because it's gear driven, so, a small digital tach would tell us the output RPM of the shaft which might translate into cubic inch,,

Disclaimer,
I'm certainly not a hydraulic experts by any stretch of the imagination,, perhaps we have a member on this site that is and could help?

 

So, I think the reason you haven't seen a response on this is because,

Although I've read and searched a lot of the old posts, I've found lots of similar questions but most (if not all) had answer that were more rhetoric in nature then actual answers.

I think, probably the best answer would be, to figure out the formula required to convert into the answer you're looking for. Then, with that formula, input the known data available,
Well, that's a mouth full, without saying a whole lot,

Anyways, finding the answer to that question, alluded me as well when I was looking at possibly having to replace a motor on one of my tillers.

CID= (GPM x 231)/RPM

So, a simple check,, 9 X 231/3600 = .557 which is "somewhat close" to what our pumps are rated for.

Of course, this one is fairly easy because it's a pump,, but with a hydr motor, the input would be gal/min, and figuring the rpm, well, not so easy because it's gear driven, so, a small digital tach would tell us the output RPM of the shaft which might translate into cubic inch,,

Disclaimer,
I'm certainly not a hydraulic experts by any stretch of the imagination,, perhaps we have a member on this site that is and could help?

But, if he's talking about the drive motor there is no 3,600 rpm input.

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This shows what a standalone hydraulic auger has in foot pounds.

This is the Case Ingersoll math from the information we produced today.

This is the ft-lbs torque that the case ingersoll motor produces. This motor should have no issues spinning a 12" auger.

 

Has anyone turned up the pumps to 3000 psi on the case ingersoll?

 

I do know that lots of pumps run at 3000 PSI and higher, but the fittings/hoses/pipe runs are a lot beefier then what we have on our tractors. Not knowing what the end goal is, and hardware used, for myself, I'd hesitate to answer that.

So Cherokee, you asked for what I suspect is a difficult answer. I do know that, on the average, our case motors will run anywhere from 140 RPM and up to 190ish. Doesn't mean other motors can't run faster or slower though.

What are you hoping to end up with, implement wise? Would there be a pressure relief in the system? I know, whenever I've purchased hydraulic hoses for my tractors, the shop that makes them, always asks for pressure of the system, and when I tell them, they in-turn indicate low pressure system,, so I think with our given pressures we use low pressures (Not saying that something with 3000 or less PSI can't hurt you, it can quite badly). As far as pressure reliefs, on our case tractors, I know the manuals state what they should be set at,, but in saying that, there are some fairly substantial differences between one tractor to the next. So, considering that the hoses/fittings/tubes (and valves look very similar) are the same used on both models, on the lift system of a 446 for example, relief pressure settings should be at or around 500 Psi (just going off memory here) but on a 646 that same pressure relief setting (for the lift on TCV) it's,, double that number at 1000 PSI (not stating book numbers, just going off rough memory). (It's an oddity that I can't help but notice) when working on these setups, and not being an engineer, I can't answer the "why of that" but I can certainly speculate that both relief settings would work either way, where as the frames would be impacted proportionally.

Anyways, somewhat off topic,,

What is it you want to end up with?

Lionel

 

Some additional information

 

I will be making a hydraulic auger.

I have a skid steer one, but that is not always advantageous for my customers because of the footprint it leaves.

I believe I can use a Case Drive motor attached to smaller augers. IE 12" and below. Looking at the little beaver screen shot I should have equal torque as those units.

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Is the foot print left behind by moving across grass or just when using auger? It would be cheaper to use 3/4" plywood ripped in half length wise to distribute weight across yards. Could be doubled to 1 1/2" if needed. I used the 3/4 all the time moving 800lb boilers across grass with a hand truck. The hand trucks would sink in if ground wasn't frozen or hard compacted. Plywood lasted 3-4 years if kept indoors. Jim

 

While that does work, it would be a pain to carry that much plywood. This is a 9000 lb skidsteer and sometimes the hole is 200plus feet away. Plywood wouldnt be practical.

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Most of the landscaper/contractors around here use tracked skid steers. driving straight across a lawn they leave no more marks than a CCI! They have to be careful turning though. My brother in Toronto rents a dedicated tracked post hole digger when he needs one. Claims you could drive it THROUGH the house to the back yard if need be.:mrgreen: I know, I know, there is a ******* joke right there!

 

Unfortunately I wont be buying one that is easy on a lawn at 10k to 11 k nothing is easy on a lawn.

Next year ill probably add a mini if the 6018 doesny work good. In the meantime it'll be modified for what I need.

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